draw the figure, you can find the two vertex offered are on the same line, then you can figure out the length of the line is 根号 29(根号(6-1)^2+(3-1)^2), so the surface of this square is (根号 29)^2=29(=5^2+2^2)
1: simplify to : is (x-y)^2>0? Well, if x not equal to y, then x-y not equal to zero, and if you square it, you get positive numbers, so 1 alone is true