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13. A three-digit code consists of digits from 0 to 9. If the first digit cannot be 0 or 1, the second digit must be 0 or 1, and the second and third digits cannot be 0 at the same time, how many codes are possible? answer: 分开算,__/__/__ 1,让第二个数字是0,8*1*9=72 2,让第二个数字是1,8*1*10=80 所以,一共是152种可能 14. A jar contains 12 balls, including three red and nine blue; another jar contains 20 balls, including eight red and 12 blue. If one ball is selected from each of the two bags, what is the probability that two blue balls will be selected? answer: (9/12)*(12/20)=9/20 15. What is the remainder when positive integer x is divided by 7 1). X+1 is divisible by 7 2). X+13 is divisible by 7 answer: Answer: D 1, remainder is 6, 2, remainder is 1 16. A company has assigned a distinct 3-digit code number to each of its 330 employees. Each code number was formed from the digits 2, 3, 4, 5, 6, 7, 8, 9 and no digit appears more than once in any one code number. How many unassigned code numbers are there? answer: P83-330=6 17. K=wxyz, where w, x, y, z are prime numbers. Not including 1 and K, how many factors does K have? answer:14. 因为不包含1 和K(K就是WXYZ), 所以,factors有4+C42+C43=14 p.s. C42是两两因子相乘的因数,C43是三个因子相乘的因数 18. Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 14 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed? answer: 20。 X+Y=30 (10X+20Y)/30=18 推出:X=6 ,Y=24 又有(10*6+20Z)/(6+Z)=14 推出:Z=4 故,24-4=20个2-pound的箱子要被移走 |