以下是引用ppbb在2006-1-10 8:29:00的发言:(5)In the xy plane, the diameter of one circle is 4, one line is perpendicular to the circle at (-sqrt(2), sqrt(2)) (注意,这儿就是“根号2 ”,我不知怎么打 ,原体没有这个问题, what is the slope of this line? My understanding: the question asks for the slope of the line which is perpendicular to the circle at(-V2,V2),not the slope of a diameter of the circle, which pass through(-V2,V2)and (0,0). Thanks
But I think the slope of the line which is perpendicular to the circle at(-V2,V2) is just the slope of a diameter of the circle, which pass through(-V2,V2)and (0,0).
请谈谈你对perpendicular 的理解,难道是相切?刚才查了一下相切的英文是tangent
[此贴子已经被作者于2006-1-10 8:53:56编辑过] |