以下是引用耳朵在2004-2-10 3:16:00的发言: 第一题,题目第一句话说的是:“each policy has a paper record or an electric record”,就是两者只居其一即可,有只有P的也有只有E的,也有两个都有的。 但是问的是P和E都正确的概率。可是不知道P和E单独的比例,因此这个算法不完整。
以下是引用耳朵在2004-2-10 3:49:00的发言: 画了个图,表示得更清楚。 [see 第32楼]题目中要求的是黄色的部分,即B。 已知A+B+C+D+E+F=1,而现在E等于(D+E)的60%,也等于(E+F)的75%,但是算不出来A和C,所以B占的比例无法求出。
Once again, if the answer must be right, then its question must be wrong... for the record: 94% is the right answer for the following questions:
- what is the probability that a policy isn't recorded incorrectly? (~P & ~E)
- what is the probability that it is one having correct paper [or] correct electric record, [or both]? (P | E)
As for the question "what is the probability that it is one having both correct paper and correct electric record?" (P & E), agree with 耳朵gg that the problem doesn't offer enough information to solve it. However, if the problem states that each policy has a paper record and an electric record, the question is solvable... a revised #1:
In an insurance company, each policy has a paper record and an electric record. 60 percent of the policies having incorrect paper record have incorrect electric record and 75 percent of the policies having incorrect electric record have incorrect paper record. 3 percent of all the policies have both incorrect paper and incorrect electric records. If we randomly pick out one policy, what is the probability that it is one having both correct paper and correct electric record?
[此贴子已经被作者于2004-6-21 0:20:43编辑过] |