以下是引用madben在2006-9-21 22:41:00的发言:111. T这个人本来有X 本书,放在书架上,每排10本,正好放完。后来T 又得到10本书,放在书架上,每排12 本,也刚好放完,求X? A 1) X<96 2) X>24 [eyda] 10n+ 10 = 12 n => n=5 => X =10n = 50 1) / 2) 都成立!为什么选A?
[eyda] 10n+ 10 = 12 n => n=5 => X =10n = 50 1) / 2) 都成立!为什么选A? 百思不得其解! 我都要疯了! 谢谢 如果原题如此,你的做法没有错。但我个人怀疑原题的意思是两次放的排数未必一样 10n + 10 = 12m, i.e. 10(n+1) = 12m The least common multiple of 10 and 12 is 60; so let 10(n+1) = 12m = 60k m=5k and n+1 = 6k; k=1, 2, 3... When k=1; n=5 and X=10n=50 When k=2; n=11 and X=10n = 110; So condition 1) X<96 is enough to determine while the second codition x>24 is not. 呵呵,刚想说是60,就被你改掉了 你的数学真好啊 谢谢你 谢谢, 想不到GMAC也会开始出一些有水平的题目拉 |