天山-6-13,24,29

neverback

Q13:
If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x < -14y
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Q24:
8
If w and c are integers, is w > 0?
(1) w + c > 50
(2) c > 48
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Q29:
June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note:
1984 was a leap year.)
A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday

MINE: C E E

ANS:  D C C

算了几遍,还是觉得我对

大家来讨论一下吧

neverback

怎么没人理我啊~~~~~~~~~

哥哥的宝宝

MM别哭。二题三题偶觉得你对了，一题偶不会算

neverback

第一题我是两选项相加的

NN在哪里?????????

Baker

I think Q13 is B,

the rest I agree with you.

Where're NNs?

neverback

我自己顶

顶到NN来......

neverback

GO ON DING

爱维的天

Q29:
June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note:
1984 was a leap year.)
A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday

I am not NN. The answer is C.         5*365+1=1726    >>    1726/7=246 + 4/7    >>    so June 25, 1987 is C ( because Friday plus 4 days)

爱维的天

Q13:
If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x < -14y
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

I am not NN. My answer is D.  
     
For condition 1
You can list the possible number of x & y and you will find
If x > y + 4, then 3x > 7y (base on x,y >0)
For example
x      y    3x     7y
>5   1   >15     7
>6   2   >18   14
and so on…

For condition 2
-5x < -14y   >>  5x > 14y  >> (5x)/2 > 7 y
because 3x > (5x)/2
so     3x > 7y

It’s time to sleep…

[此贴子已经被作者于2004-12-19 0:09:02编辑过]

neverback

condition 1

0<y<3 ify=2   x>y+4=6   3x>18>7y=14    确定

y>3     ify=4   x>y+4=8   3x>24   7y=28   不确定

so condition 1不成立

condition 2

5x>14y   x>2.8y

3x>8.4y>7y

so ans is B

TO BE DISCUSSED...