One math Q. in Oct. JJ, help!

Levy

12. （九月jj）定义[X]是大于等于X 的最小的整数，[X]=0，求X=?

answer: -1<X<0

I can't figure out. Could sb help me with this? thanks!!!

garving2001

answer should be -1<x<=0

从条件来看，首先你可以得出   x<=0

如果x<=-1的话，[x]=-1, 与条件不符。所以，-1<x<=0

Levy

got it, thanks