两道PP3题，泣血不会，惨

tweib

1、A store currently charges the same price for each towel that it sells .If the current price of each towle were to be increased by $110 fewer of towel could be bought for $ 120, excluding sales tax , what is the current price of each towel?

答案是$3

这个题，关键可能在fewer,　晕

2、For a certain set of n numbers ,where n>1,is the average(arithemetic mean) equals to the median?

1) If the n numbers in the set are listed in increasing order,then the different between any pair of successive number in the set is 2

2)the range of the n number in the set is 2(n-1)

对于条件1，我还想分n是偶数，奇数，分着分着就晕了

[此贴子已经被作者于2004-7-28 16:54:19编辑过]

blackhorse

1、120/x=120/(x+1)+10 得X＝3

2、选A。等差数列的median＝average

麻集爱

第一题有问题吧?你敲全了没？？＼

第二题，ｂ　是错的，　看ａ　：题目给的是等差数列．　你带两对数进去嘛，　

１３５７

３５７

这两组数试试就ｏｋ了，　至于偶数例子想包含在这两给例子里了，　如果非要举例也很快．　

应该是ａ．

一剑穿心

第一题，我的理解：

如果当前每一个毛巾的价格提高110元的话，（库存）较少的毛巾可以卖120元。

对否。题目不全！？

第二题：

由1）知道是等差数列，所以本应该选A)

但为什么有个if，所以最终选E

bcbc

第一题不明白.

第二题我选A,不过没把握,楼主有正确答案吗?再看看别人的结果吧.

applicationy

第一题好像题目确实有问题

第二题肯定选A，没问题

tweib

骂我吧，我丫该！经过XDJM的提醒：再次杀入PP3，发现真正吐血的原因：A store currently charges the same price for each towel that it sells.If the current price of each towle were to be increased by $1, 10 fewer of the towels could be bought for $ 120,－－－

踩我吧，我居然将那逗号认为是$1, 10

至于第二题，还真不会，今天才明白，“何处能寻这般良友”

一剑穿心

第二题的if不重要，中数本来就要求排序。A 正确