2006年9月份jj讨论稿第6篇出炉（375题开始，每天更新）

QiiQ

以下是引用systemunknow在2006-9-23 6:00:00的发言：

讨论：条件1由于不知道税率。所以，不能肯定了tax外＞１５。条件2由于不知道找回的零钱数，所以，也不能肯定了tax外＞１５。两条件联立：若给出C为正整数的条件，则有此物除了tax外＞１５.因为，c最大为4，根据已知条件可知，此物税前价格为16，除税后为15.04。若未给出C为正整数的条件，则不能肯定此物除了tax外＞１５。

So the answer is E ... that's what people were saying.... 

thank you systemunknow~~ thanks for answering~~

你的意思是说，税和找回零钱数，都有可能是负的，所以都无法判断？

stewiegriffin

以下是引用systemunknow在2006-9-23 6:00:00的发言：

讨论：条件1由于不知道税率。所以，不能肯定了tax外＞１５。条件2由于不知道找回的零钱数，所以，也不能肯定了tax外＞１５。两条件联立：若给出C为正整数的条件，则有此物除了tax外＞１５.因为，c最大为4，根据已知条件可知，此物税前价格为16，除税后为15.04。若未给出C为正整数的条件，则不能肯定此物除了tax外＞１５。

So the answer is E ... that's what people were saying.... 

可是没有听说过买东西会倒赔税的，税和找回来的钱都不应该是付数。 条件1可知原价+税=15(这里注意看已经不大于15了)。税不可能是付的，既然原价+税=15，那原价就不可能大于15，可能等於或小於5，但不会大於5。条件一sufficient.

我说的是418题，这里说C=5。 第5题说的是C<5。  systemunknow,你是不是说的不是一个题呢？  thank you.  I'm pretty sure I'm right...

[此贴子已经被作者于2006-9-23 9:36:10编辑过]

madben

以下是引用stewiegriffin在2006-9-23 9:27:00的发言：

可是没有听说过买东西会倒赔税的，税和找回来的钱都不应该是付数。 条件1可知原价+税=15(这里注意看已经不大于15了)。税不可能是付的，既然原价+税=15，那原价就不可能大于15，可能等於或小於5，但不会大於5。条件一sufficient.

我说的是418题，这里说C=5。 第5题说的是C<5。  systemunknow,你是不是说的不是一个题呢？  thank you.  I'm pretty sure I'm right...

我同意税率肯定不会为负，虽然有可能稅率为0。
我相信原题给的条件应该不会是这样。不管怎样，只要知道怎么根据税率P和找回多少钱C来计算稅前价格就行。不用计较JJ的答案怎么样。
价格=（20-C）/（1+P）

[此贴子已经被作者于2006-9-23 12:19:01编辑过]

stewiegriffin

以下是引用callum在2006-9-22 7:12:00的发言：

412．A company get a 50000 dollar contact of a project, the project only cost labor and material, 问profit is larger than 15000/

  1).Labor cost is twice the cost of material

  2) Profit is larger than Labor cost----she choose E,too. 我统一选E。
   
                    

讨论： C

为什么是C???我觉得应该是E啊.....感觉有点莫名其妙的

5．A company get a 50000 dollar contact of a project, the project only cost labor and material, 问profit is larger than 15000/

  1).Labor cost is twice the cost of material

  2) Profit is larger than Labor cost----she choose E,too. 我统一选E。

50000-L-M=P ==> 50000-L-L/2=P because P>L ==>50000-L-L/2>L ==> 20000>L

From 2) P>L and 20000>L We can not conclude that P>20000

But from L<20000 ==> 3/2*L<30000 (where 3/2*L= L+M) ==> - 3/2*L> -30000

                              ==>50000-3/2*L>50000-30000 ==>>20000         

5．A company get a 50000 dollar contact of a project, the project only cost labor and material, 问profit is larger than 15000/

  1).Labor cost is twice the cost of material

  2) Profit is larger than Labor cost----she choose E,too. 我统一选E。

50000-L-M=P ==> 50000-L-L/2=P because P>L ==>50000-L-L/2>L ==> 20000>L

From 2) P>L and 20000>L We can not conclude that P>20000

But from L<20000 ==> 3/2*L<30000 (where 3/2*L= L+M) ==> - 3/2*L> -30000

                              ==>50000-3/2*L>50000-30000 ==>>20000         

为什么是C???我觉得应该是E啊.....感觉有点莫名其妙的

5．A company get a 50000 dollar contact of a project, the project only cost labor and material, 问profit is larger than 15000/

  1).Labor cost is twice the cost of material

  2) Profit is larger than Labor cost----she choose E,too. 我统一选E。

50000-L-M=P ==> 50000-L-L/2=P because P>L ==>50000-L-L/2>L ==> 20000>L

From 2) P>L and 20000>L We can not conclude that P>20000

But from L<20000 ==> 3/2*L<30000 (where 3/2*L= L+M) ==> - 3/2*L> -30000

                              ==>50000-3/2*L>50000-30000 ==>>20000         

5．A company get a 50000 dollar contact of a project, the project only cost labor and material, 问profit is larger than 15000/

  1).Labor cost is twice the cost of material

  2) Profit is larger than Labor cost----she choose E,too. 我统一选E。

50000-L-M=P ==> 50000-L-L/2=P because P>L ==>50000-L-L/2>L ==> 20000>L

From 2) P>L and 20000>L We can not conclude that P>20000

But from L<20000 ==> 3/2*L<30000 (where 3/2*L= L+M) ==> - 3/2*L> -30000

                              ==>50000-3/2*L>50000-30000 ==>>20000         

这都能做出来？ 好厉害=)

stewiegriffin

以下是引用madben在2006-9-23 9:43:00的发言：

我同意税率肯定不会为负，虽然有可能稅率为0。
我相信原题给的条件应该不会是这样。不管怎样，只要知道怎么根据税率P和找回多少钱C来计算稅前价格就行。不用计较JJ的答案怎么样。
价格=（20-C）/（1-P）

you're right madben.  Sorry about that. I'm a little stubborn sometims.  just have to pay attention to the question at the exam.  Thanks

 

systemunknow

hmm not sure if I am doing this right but the way I did was:

1) Cost of Labor = x,  Material= 2x,

2) Profit > Cost of Labor x

However, if profit = 20,000 we have 30,000/3 = 10,000 which holds true for 1) and 2)

But at profit = 14000 we have  36000/3=12000 which holds true for 1) as wellas 2)

So I choose E since I can have it at both ways, how did you choose C?

Remember Labor + material does NOT = 50,000 you have to include in profit as well..

for more infor go to: http://forum.chasedream.com/dispbbs.asp?boardID=22&ID=195279&page=2

I think the Answer to that question is E...

stewiegriffin

以下是引用systemunknow在2006-9-23 10:53:00的发言：

hmm not sure if I am doing this right but the way I did was:

1) Cost of Labor = x,  Material= 2x,

2) Profit > Cost of Labor x

However, if profit = 20,000 we have 30,000/3 = 10,000 which holds true for 1) and 2)

But at profit = 14000 we have  36000/3=12000 which holds true for 1) as wellas 2)

So I choose E since I can have it at both ways, how did you choose C?

Remember Labor + material does NOT = 50,000 you have to include in profit as well..

for more infor go to: http://forum.chasedream.com/dispbbs.asp?boardID=22&ID=195279&page=2

I think the Answer to that question is E...

我觉得还是C。 20,000和14,000 is a valid point, but profit won't be greater than labor cost in that case.   I think you only proved that the anwser is not A, B or D.  However, if you use both condition (1) and (2), you can solve the problem. 

It's just my take.  look at callum's post, it makes a lot of sense to me.  I'm still not sure...  hope I won't get this question on the exam..=)

[此贴子已经被作者于2006-9-23 11:09:06编辑过]

欧阳逸尘

谢谢evelynyeh4010，偶秀逗了。

systemunknow

nvm

[此贴子已经被作者于2006-9-23 13:23:58编辑过]

inlovesummer

以下是引用madben在2006-9-21 8:22:00的发言：

376. 有140本书，分给N个人，每人至少两本，问N有几种可能
    
    

10

N有几种可能 等同于140有多少个不同的小于140的因子

140 = 2^2 * 3^1 * 5^1

N = (2+1) * (1+1) * (1+1) - 1 = 11; So the answer should be 11.

FYI -

Generally, if n = m1^k1 * m2^k2 * m3^k3 * ...

The total number of factors of n = (k1+1) * (k2+1) * (k3+1) * ....

i support this!!!!!