天山-7－22，答案有问题！请大家确认一下

skyalan

答案为C，我认为it should be D

文章提到的是人们收到violate crime的侵犯率，C提到violate和inviolate的比率，是无关选项。

而D所说的四年前原本的violate rate才是argument所真正fails to take account的。没有这个数字，仅仅凭增加率，不能说M的人比P的人跟容易受到violate crime的侵犯

请大家确认一下

爱维的天

我的參考答案是(D),我也覺得是(D).

dhxy

有没有NN出来解释一下这道题？

Pudding

不能複製, 手打的, 請大家幫忙看看:

The violent crime rate (number of violent crimes per 1,000 residents) in M is 60% higher now than it was 4 years ago. The corresponding increase for P is only 10%. These figures support the conclusion that residents of M are more likely to become victims of violent crime than are residents of P.

The argument above is flawed because it fails to take into account:

B how the rate of population growth in M over the past 4 years compares to the corresponding rate for P

D the violent crime rates in M and P 4 years ago

我同意D是對的, 可是B是在講什麼啊? "how the rate... compares to..." 腦筋轉不過來, 它是在說誰跟誰比, 比什麼啊?

brace

B: M和P在过去4年里面，人口增长的比例互相对比是怎么样的。

beautywawa

參考看看吧

7-22   http://forum.chasedream.com/dispbbs.asp?boardID=24&ID=88572&page=1

Pudding

謝謝brace gg...

謝謝喵版主... 可是妳的連結又連回來這個貼了...

lawyer_1

答案为D无疑。

原文结论的意思实际为：现在M和P哪个犯罪率高。

在得出这个结论时原文提出的证据是和四年前比的数据，即以四年前的犯罪率作为基础，所以要比较现在的犯罪率，必须比较四年前的犯罪率。如果四年前M的犯罪率比P低很多很低，那末虽然这四年M的犯罪率增长达，但现在的犯罪率也会比P低。原文没考虑这种可能性。即D

B的意思为在过去四年里，M和P的人口增长率相比情况。因为犯罪率本身已算进了人口增长，所以不必再考虑人口增长情况。B是无关项。

hhnelson

lawer ,讲得好!!

armstrong

可是E呢？如果P城的犯罪率低是因为防范力量极强，导致人们不敢犯罪，岂不是也对？

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

ED（四年前可能极低，但E应该也可以啊？）

Changes in the population density of both Meadowbrook and Parkdale over the past four years.

How the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

The ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

The violent crime rates in Meadowbrook and Parkdale four years ago

How Meadowbrooks’ expenditures for crime prevention over the past four years compare to Parkdale’s expenditures.