一题绕绕的逻辑 求大神解答

song4444

In Rubaria, excellent health care is available to virtually the entire population, whereas very few people in Terland receive adequate medical care. Yet, although the death rate for most diseases is higher in Terland than in Rubaria, the percentage of the male population that dies from prostate cancer is significantly higher in Rubaria than in Terland.

Which of the following, if true, most helps to explain the disparity between the prostate cancer death rate in Rubaria and Terland?

A.      Effective treatment of prostate cancer in its early stages generally requires medical techniques available in Rubaria but not in Terland.

B.       Most men who have prostate cancer are older than the average life expectancy for male inhabitants of Terland.


C.      Being in poor general health does not increase one’s risk of developing prostate cancer.

D.      It is possible to decrease one’s risk of getting prostate cancer by eating certain kinds of foods, and such foods are more readily available in Rubaria than in Terland.

E.       Among men in Rubaria, the death rate from prostate cancer is significantly higher for those who do not take full advantage of Rubaria’s health care system than for those who do.

有木有同学也碰到这题的，为什么B是对的啊？？   
网上很多解释说选B因为 T 地很多人根本活不到患cancer年龄就死了所以能够解释原文disparity.但是 明显题目是说两地已经得cancer的人群中 R的死亡率要比T高  
如果按照B的说法  那么就是说T地本来可以从cancer中痊愈的人 会因为其他病而死亡，所以相比R地来说T地的死亡率反而要高了 明显是weaken 原文的嘛。。 求大神解答

soulwangh

hi,

Your reasoning is correct.
The reason that death rate of T in the person who have cancer is lower than that of R is people who have cancer in R will die from other factors which relates with aging.
In contrast, people in T are young and more likely have less illness except for the cancer.

超超为杰

用helr的方法试一试
这是一道类比推理。R的hc比T的hc多，所以R的死亡率就比T的低。由此应类比出结论R的pc也应比T的低，但结论却是T的比R的低。说明RT之间存在差异。按HElr的方法，类比推理要找的就是类比对象之间的不同和反案例。
A其实是复述的原文；
B涉及到了RT两国的患PC的人的差异，保留；
C不涉及RT差异；
D涉及到RT的差异，保留；
E不涉及RT的差异；
比较B、D，可发现D实际是对患PC的RT之间的差异的反驳，而非解释结论。故B正确。

VinegarValley

超超为杰 发表于 2013-11-23 09:26
用helr的方法试一试
这是一道类比推理。R的hc比T的hc多，所以R的死亡率就比T的低。由此应类比出结论R的pc也 ...

同意！