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NN帮看看这道题,猪和牛的问题,看起来好简单哦,为什么我错了

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楼主
发表于 2004-9-3 23:06:00 | 只看该作者

NN帮看看这道题,猪和牛的问题,看起来好简单哦,为什么我错了

Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?


(1)    The farm has more than twice as many cows as it has pigs.


(2)    The farm has more than 12 pigs.

沙发
发表于 2004-9-3 23:48:00 | 只看该作者

答案是c吗?

由1:(60*2/3)/3 =13.33 ==〉 40-13=27< cows

由2: no less than 12 pigs ==>  40-12 =28 >= cows

故由1和 2 ==〉 cows=28

板凳
发表于 2004-9-4 06:00:00 | 只看该作者
c
地板
发表于 2004-9-4 10:24:00 | 只看该作者
The farm has  twice as many cows as it has pigs.The sentence means that there are two times as many cows as there are pigs. So, if there are 8 pigs, there are 16 cows,  This is the kind of question that is on an IQ test. They make you think a lot.Here is a "Super IQ Test" you can practice on: http://web.tickle.com/tests/superiq/index.jsp
5#
发表于 2004-9-4 12:22:00 | 只看该作者
A?
6#
 楼主| 发表于 2004-9-4 13:43:00 | 只看该作者
Y. C is right.
7#
发表于 2004-11-7 21:23:00 | 只看该作者

不对!我认为是E。

原题的表达应理解为:

题干:        pig+cow=60*2/3=40

(1)cow>2*pig

(2)pig>12

1和2都是不等式,而且都是开区间,怎么得出C来呢?二楼的看法我有不同意见,pig>12只能推导出cow<28,=号是怎来的呢?



[此贴子已经被作者于2004-11-8 10:52:01编辑过]
8#
发表于 2004-11-8 00:03:00 | 只看该作者

我是这么想的,pig>12,取第一个值13,则cow>2*13, cow取第一个值27,正好13+27,成立,如取第二个值28, 13+28>40, 不成立,故pig=13, cow=27这组是对的。

如pig取第二个值14, 则cow>2*14, cow 取第一个值29, 14+29=43>40, 不成立。

由此可看出只有一组成立,故选C。

9#
发表于 2004-11-8 11:49:00 | 只看该作者

Bingo, jnlvo is right.

10#
发表于 2012-11-3 19:55:50 | 只看该作者
答案是c吗?
由1:(60*2/3)/3 =13.33 ==〉 40-13=27< cows
由2: no less than 12 pigs ==>  40-12 =28 >= cows
故由1和 2 ==〉 cows=28
-- by 会员 rabbit (2004/9/3 23:48:00)

谢了~我太傻了
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