AA:“The country of Sacchar can best solve its current trade deficit problem by lowering the price of sugar, its primary export. Such an action would make Sacchar better able to compete for markets with other sugar-exporting countries. The sale of Sacchar’s sugar abroad would increase, and this increase would substantially reduce Sacchar’s trade deficit.”
AI:Everywhere, it seems, there are clear and positive signs that people are becoming more respectful of one another's differences.
If r@s=s@r, then which of the following is true? @代表符号,没记错的话应该是这样,这题我也完全没头绪 I. r@s = r + s -rs II. r@s = (r+s)(r-s) III. r@s = s/r + r/s 选项是什么I,II or I, III, or...or 全部
罗技: 农民们都很后悔去年玉米卖早了,因为后来玉米价格上涨。今年又是一个丰收年,而且因为xxx原因,玉米的价格也expected to increase,但是很多农民已经开始大量卖玉米了,问解释。 我选的是因为玉米大丰收,好多农民没有地方存这么多玉米。
说有个地方种葡萄酿酒,有一年的天气很好,温度和什么都balance的很好,葡萄成熟的时候酿出来的酒怎么怎么样。今年天气预计变化很大,温度和湿度都没那么稳定。说什么葡萄温度高的时候甜度会增加还是减少,而酸度却因为另一个条件减少或增加,问如果这个情况是确定的,那以下哪个可能发生? 1是什么种葡萄的人可能会要种另一种葡萄which tolerate more with the high temperature 2是什么种葡萄的可能要换到和以前天气情况差不多的地方去种葡萄 3,4忘了 5是今年的葡萄酒味道和以前会不一样 (我选的是这个,不确定)
刚看到别的狗主人的题,借来用用,补充个选项,因为我选错了…… -.-||| 说一个地方农村什么设施不好,哪一年只有45%的人喝上干净水,后来哪一年有70%的人能喝上干净水,所以政府有对于农村设施有很大的improvement什么的。问weaken。那个狗主人选的是D.就是说后来的那一年很多农村人都进城打工去了,我选的是另一个,应该是错了,说什么现在城市里有90%的人都有access to clean water。
第三篇狗狗上那个修摩托车的,第一段说修摩托车的人需要多方面来诊断问题的所在,有时候需要imagine scenarios什么的,每个修理公司要承担修理的成败。第二段说不同的车修理的costs不同,因为采取的approach不一样。然后举了一个什么老爷车的例子,the screws of the engine cover已经没得卖了,问难道你要冒着把螺丝拆下来可能会导致整个引擎报废的风险来检查引擎吗?最后说什么摩托维修工的工作好坏是没有固定rules来判定的。
If r@s=s@r, then which of the following is true? @代表符号,没记错的话应该是这样,这题我也完全没头绪 I. r@s = r + s -rs II. r@s = (r+s)(r-s) III. r@s = s/r + r/s 选项是什么I,II or I, III, or...or 全部
DS:问N是不是differences of two prime numbers (1)N=11 (2)(N-7)(N-11)=0 这题我不会做,蒙的
(1) is sufficient. 2 and 13 (2) is insufficient. Since the difference cannot be 7. 2+7 =9 and 9 is not prime. However the difference could be 11. So this is a 50/50 and we cannot for sure to say N is the difference between 2 prime numbers.
What this question is testing is to "commute" the two variables. Meaning let New s = Old r and New r = Old s. Then test if the result of New is the same as the result of the Old. Simple algebra.  ay attension to signs. For example (r-s) = -(s-r)