为何是D呢？应该是要知道具体数字之类的吧~

frankzhiwei

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

A.Changes in the population density of both Meadowbrook and Parkdale over the past four years.

B.How the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

C.The ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

D.The violent crime rates in Meadowbrook and Parkdale four years ago

E.How Meadowbrooks’ expenditures for crime prevention over the past four years compare to Parkdale’s expenditures.

为何是D呢？知道了也还是增长了那么多呀~

candyb110

犯罪率=之前的+增长的
之前的低的话，增长的多，也不一定犯罪率高于之前的高，加上增长的少

bonfin

这里增长的相对比例高不代表增加的绝对数就多，所以要看原来的比例是多少，如果原来基数低，即使增加比例大于后者也可能总犯罪人数比后者低。结论中的more likely是针对于人口绝对数而言的，而不是针对比例而言。