[求助]2道DS题，大家帮帮忙呀``````````

gill0324

1.Susan has selected exactly three crayons, each a different color, from a crayon box.How many crayon colors were represented in the box before her selection?(C)

(1)Exactly four distinct three-crayon color combinations were represented in the box before Susan selected three crayons.

(2)Just before Susan's selections,the box contained exactly five crayons.

A.Statement 1 ALONE is sufficient,2 is not.

B.Statement 2 ALONE is sufficient,1 is not.

C.Both 1 and 2 TOGEHTER are sufficient,but NEITHER  ALONE is sufficient.

D.EACH ALONE is sufficient.

E.1 and 2 TOGETHER are NOT sufficient.

这题不明白意思，希望能讲解下。

2.Three salespeople--A,B,and C--sold a total of 500 products among them during a particular month.During the month,did A sell more products than B sold as well as more products than C sold?(A)

(1)A sold 166 products during the month.

(2)C sold 249 products during the month.

A.Statement 1 ALONE is sufficient,2 is not.

B.Statement 2 ALONE is sufficient,1 is not.

C.Both 1 and 2 TOGEHTER are sufficient,but NEITHER  ALONE is sufficient.

D.EACH ALONE is sufficient.

E.1 and 2 TOGETHER are NOT sufficient.

对于划线部分我的理解是A比B和C卖的都多，但是如果A卖出了166个，那么B和C肯定有卖的比A多的。请大牛指点。

biglin1987

括号里是正确答案么？

时间造物

2.Three salespeople--A,B,and C--sold a total of 500 products among them during a particular month.During the month,did A sell more products than B sold as well as more products than C sold?(A)

(1)A sold 166 products during the month.

(2)C sold 249 products during the month.

题意。其实就是A+B+C=500，问A>B?   A>C?

(1)A=166  (2)C=249

仅从1来看，B+C=334，所以不能确定A与B，C单独的比较

（2）得到  A+B=251，同样不能确定，所以只能1，2结合，选C

时间造物

1.Susan has selected exactly three crayons, each a different color, from a crayon box.How many crayon colors were represented in the box before her selection?(C)

(1)Exactly four distinct three-crayon color combinations were represented in the box before Susan selected three crayons.

(2)Just before Susan's selections,the box contained exactly five crayons.

题意为：S从一个盒子里选了3个C，颜色各不相同，问，在选之前，盒子里的C一共有多少种颜色

条件1，在选之前，盒子当中有任选3个所组成的颜色，有四种。

条件2，在选之前，盒子中一共有5个C

分析：任选3个搭配，可以有四种不同的颜色组合，那么也就是Cx  3=4，可以得到X，就是颜色，所以选A

条件2单独无意义

wusuyao

1是说在取蜡笔前里面有4种不同的取三支笔的颜色组合。2是说取之前有5支笔

单看1的话因为这4种组合里可能有一种里包含两种一样的颜色（红红蓝），所以如果

一共有4种颜色的4支蜡笔满足1（c43不知道怎么打。。汗）或者是三种颜色但其中一种有3支（红红红蓝黄）。所以1是不能单独确定的。加上2就可以了，选c

第二题的话应该是理解成A比B多且比C多，这样的话，条件1里A少于500的三分之一，故肯定有一人比他多，这样A比B多且比C多久肯定不成立了

gill0324

我有点明白了，括号里写的是书上给出的正确答案。

1.如果条件1单独是不能确定有几种颜色的。因为假设有ABCD四种颜色，那就会有{ABC}{ABD}{ACD}{BCD}四种组合；但假设有AAABC三种颜色，就也会有{ABC}{AAB}{AAC}{AAA}四种组合。同样的条件2单独也是不能确定有几种颜色的。只有1和2同时才会使条件充分，有5支笔，4种不同的组合方式，对吧

2.Three salespeople--A,B,and C--sold a total of 500 products among them during a particular month.During the month,did A sell more products than B sold as well as more products than C sold?(A)

(1)A sold 166 products during the month.

(2)C sold 249 products during the month.

关于这题，我又想了下，是不是问的是在这个月A能比B和C卖的多么？条件1中A小于三分之一所以答案是NO，条件2中因为C=249，A的选择范围就在0-251之间，如果A为250，251，就比BC高；如果A在0-249就不高于BC，所以这题选A，因为A能给出明确答案，是这样的么？主要是对划线部分的意思无法理解。

时间造物

我觉得此题就是分别比较