In the xy-plane, the vertices of a triangle have coordinates (0,0), (3,3), and (7,0). what is the perimeter of the triangle?
A. 13
B.根号34
C.根号43
D. 7+6根号2
E. 12+3根号2
我求得斜边=根号58,周长=10+根号58,可选项里没这个答案,请各位多多赐教!
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不是 10+v(58), 应该是 12+3v(2). 你想想, 底边是7, 靠左边的那个斜边是 更号(3^2+3^2)= v(18)=3v(2), 靠右边的那个是5, 因为是直角, 另两边是3 and 4. So, the perimeter should be 5+7+3v(2) = 12 + 3v(2). It's E.
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