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452 a的負2次方 >a負3次方>a的負一次方 453 D 454 TV/Calbe 34% 無455 456 D 457 C 458 459 原JJ答案1:1 (編號有誤又重覆450) 鞋子打折20% or 19.6% ; 院子种树选 (D) 451 -24 452 6 453 B 454 C 455 C 456 5% 457 C 458 B 459 B 460 52= (X+1) * 4 =4X+4 →4X= 48→X=12 461 选1 462 a>根号2或<负根号2 463 2 464 2^18x3^12x5^6 465 20% 466 2 to 40 inclusive the sum of consecutive even number is 420 1 to 39 inclusive the sum of consecutive odd number? Is 400 467 B 468 条件2太怪异了 此数列中median不可能是1 469 470 I chose -1/2 471 D 472 1&2 473 根据题目可知K≥L≥M≥N≥O≥P,要求最大的O,故K=L=M=N=21% 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million 474 r^2(pai-1)/2 475 D 476 B 477 A 478 x=-7 479 480 D 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million 474 r^2(pai-1)/2 475 D 476 B 477 A 478 x=-7 479 480 D 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million 1 to 39 inclusive the sum of consecutive odd number? Is 400 467 B 468 条件2太怪异了 此数列中median不可能是1 469 470 I chose -1/2 471 D 472 1&2 473 根据题目可知K≥L≥M≥N≥O≥P,要求最大的O,故K=L=M=N=21% 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million 474 r^2(pai-1)/2 475 D 476 B 477 A 478 x=-7 479 480 D 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million 474 r^2(pai-1)/2 475 D 476 B 477 A 478 x=-7 479 480 D 60 million * (100%- 21%*4) = 9.6 million 9.6 million – 2million 可得the greatest number of population of O =7.6 million
[此贴子已经被作者于2008-9-29 5:50:54编辑过] |