KenzoPeace版的第147题的Key应该是B

edmund_zh

147.  y = (ax+p)^2 +k ，
            问与x轴有没有交点。

(1) a<0

(2) k >0

我选的E

Ans: 好像是C

与x轴相交的判别式 D=b^2-4ac

y = a^2x^2 + 2apx + p^2+k

D = (2ap)^2 – 4*a*(p^2+k) ← a<0; k>0 可知 4*a*(p^2+k)必为负，则D > 0 与x轴有交点

The answer should be B, because when k>0, the left side of the equation should be > 0, so there's no proper x to get y=0.