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请教两题如何求解?

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楼主
发表于 2007-11-23 08:45:00 | 只看该作者

请教两题如何求解?

1.Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y.  At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?

 

A.      4

B.      6

C.      8

D.     10

E.      12

Answer:

2.For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of the following must be true?

 

 

I.                    n is greater than zero.

II.                 3n = (-3)n

III.               √2n  is an integer.

 

 

A.   I only

B.    II only

C.   I and II

D.   I and III

E.    II and III

 

 

I.                    n is greater than zero.

II.                 3n = (-3)n

III.               √2n  is an integer.

 

 

A.   I only

B.    II only

C.   I and II

D.   I and III

E.    II and III

沙发
 楼主| 发表于 2007-11-23 11:29:00 | 只看该作者
又没有人帮忙解答一下呀
板凳
发表于 2007-11-23 13:12:00 | 只看该作者

1.Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y.  At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?

 

A.      4

B.      6

C.      8

D.     10

E.      12

Answer:

这个题可以列方程式 两个 然后解联立方程 设x每天生产xw产品 y每天生产yw产品

1-----w/xw-w/yw=2

2-----(5w/4)/(wx+wy)=3 但是我觉得简便方法就是往里面带数 答案e说 是12天 那么 x的生产效率是 每天w/6 产品 y是w/4 你会发现带进去刚刚好 考试的时候 往里面带数好了

地板
发表于 2007-11-23 13:15:00 | 只看该作者

2.For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of the following must be true?
            

 

 

I.                    n is greater than zero.

II.                 3n = (-3)n

III.               √2n  is an integer.

这个题 还是带数好了 对于这种必然有结果的题 带数是最方面的

发现 提干成立的时候 n为偶数  所以答案选2和3正确 选e

 

 

I.                    n is greater than zero.

II.                 3n = (-3)n

III.               √2n  is an integer.

这个题 还是带数好了 对于这种必然有结果的题 带数是最方面的

发现 提干成立的时候 n为偶数  所以答案选2和3正确 选e

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