GWD-8-Q21 GWD-2-18 没人讨论吗？答案D为什么不是C

toil

GWD-8-Q21:GWD-2-18   support

Last year all refuse [C1] collected by Shelbyville city services was incinerated.  This incineration generated a large quantity of residue [C2] ash.  In order to reduce the amount of residue ash Shelbyville generates this year to half of last year’s total, the city has revamped its collection program.  This year city services will separate for recycling enough refuse to reduce the number of truckloads of refuse to be incinerated to half of last year’s number. 

Which of the following is required for the revamped collection program to achieve its aim?

A.       This year, no materials that city services could separate for recycling will be incinerated.

B.        Separating recyclable materials from materials to be incinerated will cost Shelbyville less than half what it cost last year to dispose of the residue ash.

C.        Refuse collected by city services will contain a larger proportion of recyclable materials this year than it did last year.

D.       The refuse incinerated this year will generate no more residue ash per truckload incinerated than did the refuse incinerated last year.[C3] 

E.        The total quantity of refuse collected by Shelbyville city services this year will be no greater than that collected last year.

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 [C1](N.)waste material that has been thrown away

 [C2]a substance that remains on a surface, in a container etc and cannot be removed easily, or that remains after a chemical process

 [C3]Correct. The program is to reduce the number of truckloads of refuse to be incinerated to half of last year’s number in order to reduce the amount of residue ash generated this year to half of last year’s total. Therefore, we must prove that the reduced refuse this year incinerated will generate less residue ash per truckload than the refuse incinerated last year.

qianrene

我跟你一样，坚决觉得给出的答案D是错误的，C是对的

D是迷惑选项

原文先说REFUSE可以产生很多RESIDE，然后说In order to reduce the amount of residue ash Shelbyville generates this year to half of last year’s total，就采取了一个计划，即第一道工序里先把REFUSE循环利用，这样REFUSE/TRUCK就低了。题目问这个计划到底能不能被实施？]

D说的是计划采取后的效果，REFUSE产生的RESIDUE变少了，但是并没有从推理过程去分析。

ximuxingji

我认为答案是C,理由有二：一是用我的傻瓜方法最后一句冒出truckload出现，则答案应该解释一下truckload,二是truckload 数量应该不变，若变多了，则缩减一半也不能达到原来的效果

will_kk

本来这道我也错了,题意没太懂,不过看了qianrene分析的题目

确信应该选D的

偶的一点愚见:

题目是说: 目的是减少RA(residue ash)到一半,措施是增加recycle的量,使得运去烧的truckloads的数量下降到一半

D说的是每辆的truckload产生RA的量不会比去年多

数量减了一半,每个的量又不会多,所以目标肯定能达到

C才是在逻辑思路外的~

qianrene

以下是引用will_kk在2007-5-26 0:54:00的发言：

本来这道我也错了,题意没太懂,不过看了qianrene分析的题目

确信应该选D的

偶的一点愚见:

题目是说: 目的是减少RA(residue ash)到一半,措施是增加recycle的量,使得运去烧的truckloads的数量下降到一半

D说的是每辆的truckload产生RA的量不会比去年多

数量减了一半,每个的量又不会多,所以目标肯定能达到

C才是在逻辑思路外的~ 

看看原文最后的推理，说的是通过循环这种方法才达到目的，当然最后问题也要着重在这个方法This year city services will separate for recycling enough refuse to reduce the number of truckloads of refuse

采取了这个方法后当然会产生D的结论“D说的是REFUSE产生RESIDUE/每辆的truckload的量不会比去年多”没有把重点放在政府采取的方法上，所以不对

will_kk

qianrene：我觉得这道题是问必要条件，这也许是造成我们分歧的主要一点

D取非结论肯定不成立，所以是必要条件，我想这点你应该是承认的

对于C，Refuse collected by city services will contain a larger proportion of recyclable materials this year than it did last year.，

larger proportion是个很模糊的概念，到底是大多少呢？取非是肯定不成立的，这就是我的思路

zhiyinfeifei

q

snooopy

以下是引用will_kk在2007-5-28 23:37:00的发言：

qianrene：我觉得这道题是问必要条件，这也许是造成我们分歧的主要一点

D取非结论肯定不成立，所以是必要条件，我想这点你应该是承认的

对于C，Refuse collected by city services will contain a larger proportion of recyclable materials this year than it did last year.，

larger proportion是个很模糊的概念，到底是大多少呢？取非是肯定不成立的，这就是我的思路

有道理，C看上去很美，但是个人觉得比去年可循环的也可以很少，文章说了政府把部门拆了，且能分出足够的recycling XXX，好象是这个意思，我们可以去质疑这点么？

boston8899

I think D is correct.

wwzyyong

The answer is C

The aim is reduce the number of truckloads of refuse to be incinerated to half of last year’s number

So, D is focusing on each truckload, not the number of truckloads.