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27 question:3 males 3females,male can’t stand between females,female can’t stand between males,how many permutations?
【answer】
Case 1. Three females together,three males plus three females together,
FFFMMM. MFFFMM, MMFFFM,MMMFFF, 4*3!*3!=144 ways
case 2. Three males together MFFFMM, MMFFFM, 2*3!*3!=72 ways
case 3. Two males two females together: FMMFFM or MFFMMF, 2*3!*3!=72 ways
answer: 144+144=288 ways
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