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求教几道,prep数学题,一点儿思路都没有。谢谢

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楼主
发表于 2011-7-2 18:49:37 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
a certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?



the table shows the number of shared of each of the 5 stocks owned by Mr Sami. If Mr Sami was to sell 20 shares of Stock X and buy 24 shares of Stock Y, what could be the increase in the range of the numbers of shares of the 5 stocks owned by Mr Sami?


Stock   number of shares
V  68
W 112
X  56
Y 94
Z 45





Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. was the total regular price of the 3 discounts greater than 15 percent of the sume of the regular prices of the 3 items?
(1) the regular price of the most expensive itme was $50, and the regular price of the next most expensive item was $20.
(2) the regular price of the least expensive item was $15.



If the terms of a sequence are t1,t2,t3,……, what is the value of n?
(1) The sume of the n terms is 3,124.
(2) The average (arithmetic mean) of the N terms is 4.

谢谢,各位大牛。
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沙发
发表于 2011-7-2 23:57:50 | 只看该作者
lz,我不是NN,但第一题我觉得可以这样做:设最小那个为X,然后剩下的十个州都是1.1X则1.1X*10=11X,11X+X=12X,得出X=11000
板凳
发表于 2011-7-3 00:14:10 | 只看该作者
第一题沙发上的朋友回答的很清楚了

第二题没看懂,不知道问的啥,能否把选项发上来看看,以窥测下到底要问什么

第三题,只需第2,3件物品总价小于最贵的那件就可以,因此(1)足够,而单独的(2)和上述分析毫无关系

第四题,求个数,若已知总数和平均数,相除即可,(1)+(2)都需要
地板
 楼主| 发表于 2011-7-3 08:58:10 | 只看该作者
Stock   number of shares
V  68
W 112
X  56
Y 94
Z 45

The table shows the number of shared of each of the 5 stocks owned by Mr Sami. If Mr Sami was to sell 20 shares of Stock X and buy 24 shares of Stock Y, what could be the increase in the range of the numbers of shares of the 5 stocks owned by Mr Sami?

选项是, 6,9, 15,18 ,21 这几个数字。、
5#
 楼主| 发表于 2011-7-3 08:59:01 | 只看该作者
谢谢,果然高手出招就不凡啊 呵呵呵
6#
发表于 2011-7-3 09:08:48 | 只看该作者
Stock那个题是求范围range, 就是最大值和最小值的差
开始是w-z=67,
买卖完是(y+24)-(x-20)=82
82-67=15
7#
 楼主| 发表于 2011-7-3 09:13:43 | 只看该作者
Stock     Number of shares
V               68
W             112
X               56
Y               94
Z                45

The table shows the number of shared of each of the 5 stocks owned by Mr Sami. If Mr Sami was to sell 20 shares of Stock X and buy 24 shares of Stock Y, what could be the increase in the range of the numbers of shares of the 5 stocks owned by Mr Sami?

选项是4,     6,   9,  15 , 10
答案是15.
8#
 楼主| 发表于 2011-7-3 09:21:52 | 只看该作者
Stock那个题是求范围range, 就是最大值和最小值的差
开始是w-z=67,
买卖完是(y+24)-(x-20)=82
82-67=15
-- by 会员 wangxsh (2011/7/3 9:08:48)


谢谢。
果然卧虎藏龙啊 呵呵
9#
 楼主| 发表于 2011-7-3 09:23:21 | 只看该作者
也就是说,我的题意没有读懂,o(︶︿︶)o 唉
太囧了。
10#
 楼主| 发表于 2011-7-3 09:42:43 | 只看该作者
另外一个
On a certain sight-seeing tour, the ratio of the number of women to the number of children was 5 to 2. what was the number of men on the sight-seeing tour?
(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5 to 11?
(2) The number of women on the sight-seeing tour was less than 30.
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