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[求助]Prep-PS-1-62

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楼主
发表于 2009-7-14 20:16:00 | 只看该作者

[求助]Prep-PS-1-62

求助一題:

Alice's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month.  The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take-home pay that she did not save.  If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?

 

(A) 1/2

(B) 1/3

(C) 1/4

(D) 1/5

(E) 1/6

正解(D)

請各位幫忙解釋為何是(D)!謝謝!!

沙发
发表于 2009-7-14 20:34:00 | 只看该作者

假设每个月拿回家为X,存的百分比为N, The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take-home pay that she did not save 这句话的意思用方程写出来就是

X*N*12=3*(1-N)*X

板凳
发表于 2009-7-14 20:55:00 | 只看该作者
这倒题目有个地方需要读清楚,那就是LS说的部分!
我用个直接数字带入的方法可能简单一些~
假设一下,全年没有省的钱为1,省的钱是 1/12×3= 1/4
这样就可以推出:全年总的take-home的钱是:1/4  + 1= 5/4, 题目问的是每个月省的钱占每月take-home的比例,
则: (1/4/12) / (5/4/12)= 1/5 (其实12不用除,因为它是分子分母同时除的数)
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