[求助]一道prep 明天考--在线等待

1, what is the greatest possible area of a triangulat region with one vertex at the center of a circle of radius 1 and the other two vertex on the circle?

ans: 1/2

请问， 如何解答， i have no idea///

谢谢。。

用计算公式

1*1*sin(夹角)*1/2

园的半径是1， 那末三角形的高不能是1啊。。

请帮解释一下。。

谢谢队长。。

这是三角形面积的另一计算公式，可以理解为由在圆上的一点像半径的那边做高就可以得到了。

got it.. right angle ..

We know that the max. area of a 4 角形 is a square, then the max. area of a 3 角形 must be a right triangle, which is half of it.

In this case b/c the radius=1, then

(1x1)/2 = 1/2

good luck tomorrow, sendme!!

thanks guys...

really appreciate your help..

good luck to all...