[求助]一道prep 明天考--在线等待

sendme

1, what is the greatest possible area of a triangulat region with one vertex at the center of a circle of radius 1 and the other two vertex on the circle?

ans: 1/2

请问， 如何解答， i have no idea///

谢谢。。

mymengming

用计算公式

1*1*sin(夹角)*1/2

sendme

园的半径是1， 那末三角形的高不能是1啊。。

请帮解释一下。。

谢谢队长。。

eleine

这是三角形面积的另一计算公式，可以理解为由在圆上的一点像半径的那边做高就可以得到了。

sinfancy

one vertex is the center of the circle, and the other two are on the circle.the area will be the greatest unless right angle

sendme

got it.. right angle ..

mbz

We know that the max. area of a 4 角形 is a square, then the max. area of a 3 角形 must be a right triangle, which is half of it.

In this case b/c the radius=1, then

(1x1)/2 = 1/2

good luck tomorrow, sendme!!

[此贴子已经被作者于2006-11-21 11:26:52编辑过]

sendme

thanks guys...

really appreciate your help..

good luck to all...

michelle423

SENDME和我一天考啊,呵呵,以为你考完了呢!+U啊,我在BJ考!