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GWD-16-7 数学 请教

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楼主
发表于 2008-11-20 16:11:00 | 只看该作者

GWD-16-7 数学 请教

A school administrator will assign each student in a group of n students to one of m classrooms.  If 3 < m < 13 < n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?

(1)   It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it.

(2)   It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it.

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

沙发
发表于 2008-11-20 18:53:00 | 只看该作者
B?
板凳
发表于 2008-11-20 23:31:00 | 只看该作者
我也觉得选b
地板
发表于 2008-11-22 15:34:00 | 只看该作者
Why B?
5#
发表于 2009-3-1 11:14:00 | 只看该作者
B
1>3n/m:  m是3-13中的某个数字,m是3的倍数或者是n的因子------不一定保证整除
2>13n/m: m是小于13的,要被整除----m必须是n的一个因子----------------SUFFICIENT


6#
发表于 2009-3-2 01:25:00 | 只看该作者

5楼的解释不对。m不能等于3。其实解释是,假若m=9,当n=15时,3n可以整除9,但是n却不能。同理,B是正确答案,因为13和m没有公约数。

7#
发表于 2009-3-2 01:36:00 | 只看该作者

我误解了5楼的,以为5楼说m=3。不好意思!

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