1. english Version:
h(100) = 2 x 4 x . . . x 100 = (2^50)x 50!. Therefore, the integers 2, 3, 4, . . . , 50 are all factors of h(100), which means that none of these integers can be a factor of h(100) + 1. Thus the smallest prime factor of h(100) + 1 must be greater than 50.