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楼主
发表于 2012-3-18 00:13:25 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
5

7

11

13

17
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沙发
 楼主| 发表于 2012-3-18 00:30:02 | 只看该作者
Lindsay can paint 1/x of a certain room in one hour. If Lindsay and Joseph, working together at their respective rates, can paint the room in one hour, what fraction of the room can Joseph paint in 20 minutes?
1

3x


x

x – 3


x – 1

3x


x

x – 1


x – 1

x
板凳
发表于 2012-3-18 00:30:09 | 只看该作者
选C吧。。。
295/15=19又2/3....615/15=41....so all even multiples of 15 between 295 and 615 are "20,22,24......40"
the sum of all even multiples of 15 between 295 and 615=11*(20+40)/2=11*3*5*2
the greatest prime factor of k=11
地板
 楼主| 发表于 2012-3-18 00:34:52 | 只看该作者
If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n12 – 12n ?
- 11
- 1
0
1
11
5#
 楼主| 发表于 2012-3-18 00:42:46 | 只看该作者
How many factors does 362 have?
2
8
24
25
26
6#
 楼主| 发表于 2012-3-18 00:43:19 | 只看该作者
How many factors does 36^2 have?
2
8
24
25
26
7#
 楼主| 发表于 2012-3-18 00:44:07 | 只看该作者
If n is a non-negative integer such that 12^n is a divisor of 3,176,793, what is the value of n^12 – 12^n ?
- 11
- 1
0
1
11
8#
 楼主| 发表于 2012-3-18 00:49:54 | 只看该作者
thanks a lot, i do not even understand the questions.....I thought math was ok, but I did not realize that it is not easy... Good luck, dear friend
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