ChaseDream
搜索
12下一页
返回列表 发新帖
00:00:00

Fact: Asthma, a bronchial condition, is much less common ailment than hay fever, an allergic inflammation of the nasal passages.Fact: Over 95 percent of people who have asthma also suffer from hay fever.

If the information given as facts above is true, which of the following must also be true?

正确答案: E

相关帖子

更多...

更多相关帖子

524

帖子

15

好友

4712

积分

ChaseDream

注册时间
2003-03-17
精华
8
解析
查看: 4622|回复: 10
打印 上一主题 下一主题

GWD-18-Q15这道题真的有问题

[复制链接]
跳转到指定楼层
楼主
发表于 2011-10-23 03:06:06 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
GWD-18-Q15
Fact:    Asthma, a bronchial condition, is much less common ailment than hay fever, an allergic inflammation of the nasal passages.
Fact:    Over 95 percent of people who have asthma also suffer from hay fever.

If the information given as facts above is true, which of the following must also be true?
A.    Hay fever is a prerequisite for the development of asthma.
B.    Asthma is a prerequisite for the development of hay fever.
C.    Those who have neither hay fever nor asthma comprise less than 5 percent of the total population.
D.    The number of people who have both of these ailments is greater than the number of people who have only one of them.
E.    The percentage of people suffering from hay fever who also have asthma is lower than 95 percent

参考答案选E
但是其实有问题。把它当成数学题来做:
A: number of people with asthma only
H: number of people with hay fever only
I: number of people with both asthma and hay feve
根据题意:
A+I<H+I
I/(A+I)>95%
可知I/(H+I)<I/(A+I), but I/(A+I)>95%, so we cannot determine whether I/(H+I) < 95%. This is to say the statement that choice E must be true is wrong!
本题无正确选项。
收藏收藏 收藏收藏
沙发
发表于 2011-10-23 11:31:03 | 只看该作者
This is a must-be-true question: inference.

Only E is true becasuse A is less common than HF.  Therefore the total number of people who have HF is bigger than that of who have A.  Then it is a simple math problem to calculate the percentages for comparison.

Two hundred people have hay fever.  One hundred people have asthma. Out of the 100 people who have asthma, 95 of them have hay fever, in other words, 95% of the people who have asthma also have hay fever.

Then out of the 200 people who have hay fever, again 95 of them have asthma.  Translation: only 47.5% of the people who have hay fever also have asthma.

Simple math.
板凳
发表于 2011-10-23 11:36:24 | 只看该作者
I/(H+I)<I/(A+I)

And 95%=I/(A+I)

Therefore, I/(H+I) < 95%
地板
 楼主| 发表于 2011-10-23 11:45:20 | 只看该作者
原文是说over 95 percent, so I/(A+I)>95%, 所以e推不出来
5#
发表于 2011-10-23 11:56:27 | 只看该作者
However, you cannot quantify "much lower than", can you?

I would give it as at least 50% lower.
6#
发表于 2011-10-23 12:09:35 | 只看该作者
In terms of math, as long as "much lower than" is "at least 5% lower than", E) is correct.
7#
发表于 2014-3-29 22:43:01 | 只看该作者
画个韦恩图吧,30秒搞定
8#
发表于 2015-8-2 01:54:21 | 只看该作者
好老的贴 我也觉得这道题真的有问题
举个反例 假设一共只有100人 100人全部得了A 题目称多于百分之九十五的人得了HF 那么设定98个人得了HF
那么所有100人里,得了HF并且得了A的人一共有98个 占百分之九十八
个人见解  求NN指正
9#
发表于 2015-8-2 10:54:17 | 只看该作者
_Ashley 发表于 2015-8-2 01:54
好老的贴 我也觉得这道题真的有问题
举个反例 假设一共只有100人 100人全部得了A 题目称多于百分之九十五 ...

given A/(A+I) > 95% and A < H, it is insufficient to prove A/(H+I) less than 95%.
10#
发表于 2015-8-2 14:27:09 | 只看该作者
zhaokai09 发表于 2015-8-2 10:54
given A/(A+I) > 95% and A < H, it is insufficient to prove A/(H+I) less than 95%.

LS跟我说的是一个意思吧   认为选项E有问题?
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2024-11-6 07:29
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2023 ChaseDream.com. All Rights Reserved.

返回顶部