The city of Workney, in raising bus fares from $1.00 to $1.25, proposed that 18 fare tokens be sold for $20.00 to alleviate the extra burden of the fare increase on the city's low-income residents. Critics suggested alternatively that 9 fare tokens be sold for $10.00, because a $20.00 outlay would be prohibitive for low-income riders.
The alternative proposal depends on which of the following assumptions?
V2. (by five626(760))现在有一种marketing的stragetegy,提供很多增值服务(比如降低送货时间还是什么的大意是这样)可以吸引更多的顾客。但是如果一个公司如果持续这样做也许会丢失一些客户_________ 我选的应该是D,大意是because of the pressure of cost,….the company can’t continue provide the services that it provided before.
和狗主选的一样
By truetreasure(740,50,39)金星曾经被陨石撞出过月亮,后来被又被陨石撞了一回就吧月亮撞跑了。 问前题 答案是第二个撞击没有产生月亮,或者产生的月亮也飘走了。
(by ouying0501)The city of Workney, in raising bus fares from $1.00 to $1.25, proposed that 18 fare tokens be sold for $20.00 to alleviate the extra burden of the fare increase on the city’s low-income residents.(18张票卖20块钱,缓解低收入居民的压力) Critics suggested alternatively that 9 fare tokens be sold for $10.00, because a $20.00 outlay would be prohibitive for low-income riders. The alternative proposal depends on which of the following assumptions? A. Low-income residents of Workney will continue to ride the buses in the same numbers despite the fare increase. B. Low-income riders would be more likely to take advantage of the savings afforded by the 9-token offer than would other riders. C. The outlay of $10.00 for the purchase of 9 fare tokens would not be prohibitive for low-income bus riders.(答案) D. The proposed fare increase is needed for the purchase of new buses for the city’s bus system. E. Buses provide the only means of public transportation in the city of Workney.
452 V1:(bylizzy709) DS:x的三次方是否小于 y 的四次方 (1)x的四次方小于y的三次方 (2)x的五次方大于y 的三次方我貌似选e 参考答案:1)x^4>x^3 y^3<y^4 ,所以1)比题目的范围小,所以可以推出题目,充分 2)不充分 选A--->should be E
这题我碰到的是x,y都是正数,问是否能推出x4<y3
条件一是x5<y3
条件二是x4<y4
这道题我算了大概三分钟,最后选了E。条件比较确定
I got C on this and here is how I got, BTW, it is the 5th version of the same question: (2) --> y>x ^3/3 (1)--> y> x ^5/3 so y > x^4/3 Let's use example to verify y=0.1 and x=0.01 -->y > x^4/3 y=4 and x=2 -->y > x^4/3
452 V1:(bylizzy709) DS:x的三次方是否小于 y 的四次方 (1)x的四次方小于y的三次方 (2)x的五次方大于y 的三次方我貌似选e 参考答案:1)x^4>x^3 y^3<y^4 ,所以1)比题目的范围小,所以可以推出题目,充分 2)不充分 选A--->should be E
这题我碰到的是x,y都是正数,问是否能推出x4<y3
条件一是x5<y3
条件二是x4<y4
这道题我算了大概三分钟,最后选了E。条件比较确定
I got C on this and here is how I got, BTW, it is the 5th version of the same question: (2) --> y>x ^3/3 (1)--> y> x ^5/3 so y > x^4/3 Let's use example to verify y=0.1 and x=0.01 -->y > x^4/3 y=4 and x=2 -->y > x^4/3