这个怎么算啊

ivydorian

Q18:
On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship.  If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?

33 1/3%
40%
50%
60%
66 2/3%

ivydorian

有没有人会 谢谢大家

driftingday

Ship Passenger: P
percent of the ship’s passengers : X
round-trip tickets and also took their cars abroad the ship: 20%P
round-trip tickets did not take their cars abroad the ship: 60%PX



20%P + 60%PX = PX

X=0.5, So answer=C

ivydorian

谢谢