[求助]5月机经问题

arundhati

我不知到讨论搞里有没有讲到这些题，因为我上网时间有限不能一个一个得搜，所以帖出来麻烦大家啦～

1 DS:一个圆半径r，有两点是直径的两头，两点在园内，问影印部分面积？
1）两个弧是半圆
2）影印部分和非影印部分各占一半(D)
lwei评价意见：同意

这道题怎么得出的D啊？我题目都没看通

9 ps:y>=3,x>=2,y<=x-9的范围那题(4月362）
  答案为8
  lwei评价意见：同意

这道题是怎么得出8的？

43 ps:对于整数n,用nth表示数列S中的每一项，nth就是由n个1组成一个数，如2th就是11,问S前40个数之和的十位数？
    答案：3

这道题有什么规律可寻吗？我死算了一下发觉很不规则哦，要是考试时死算好浪费时间哦

110 ds: 有一道DS题，好象一正方形的4个顶点的问题，没看太懂，
    1 4个点都在坐标轴上，
    2 中心在原点。
    胡乱选了A，估计错了。
A
正方形的四个定点怎么可能都在坐标轴上啊，很难想象啊。答案真是A啊？

111 ps:10个字母，从中取5个和取4个组成单词的比是多少？字母都不重复。   6：1

6:1

这个答案怎么时6：1呢？我算了一下时6：5啊，C10－5/C10－4对吧？

187 PS：A(1, -1), B(-1, 1), ABC构成直角三角形，问哪个不可能是C，有选项C（2，2）；C（3，5）。     lwei评价意见: (3,5)不是

这个我觉得(3,5)是啊，我算了这点分别到A，B的距离，然后算AB的距离。这三个距离满足勾股定理啊，所以可以是C啊。

simkeechai

for question 43.
40 unit digits of 1 = 40*1 = 40, therefore unit digit is 0
since 1st of n is = 1
2nd of n is 11, 3rd is 111, and so forth until 40, then the tenth unitis equal to 39*1 = 39, plus the 4 from the sum of 40 digit units,therefore tenth digit is equal to 39 + 4 = 43, where the 4 is thehundredth digit and 3 is the tenth digit

arundhati

Thanks a lot, crystal clear now. How about other questions?

simkeechai

for Q1, i think you have to refer back to april's or march's JJ, there's a same question in there with figure drawn

for Q110, it's possible for a square to have all its vertices fall on the x and y axises, imagine a right diamond shape with points (0,1), (1,0), (0,-1), and (-1,0)

[此贴子已经被作者于2004-6-9 23:31:36编辑过]

warlord88

以下是引用simkeechai在2004-6-9 23:24:00的发言：

for Q1, i think you have to refer back to april's or march's JJ, there's a same question in there with figure drawn

for Q110, it's possible for a square to have all its vertices fall on the x and y axises, imagine a right diamond shape with points (0,1), (1,0), (0,-1), and (-1,0)

难道0,2   2,0   0,-2   -2,0不行吗