1) 10*n = 6*100 +b'*10. If so, then n = 6*10 + b', so a = 6. Sufficient. 2) n+1 = 10*7 + b'. If so, then n = 10*7 +b'-1. If b'=0, then n=10*6 +9, a=6. But if b'=1,2,3, ...9, then n=10*7 + (b'-1), a = 6. In sufficient.
Another way to analyze the second condition is to use REAL number. Let n+1 equal 70 and 71, what is the value of a? a=6 for the former while a = 7 for the latter. In sufficient.