又遇到一道输血藏獒！！ 我都快被咬死了 救命！！

junyihuo

98.    DS:一个盘上有6个点， 问能否知道连接所有点所用最少的直线？
A. 一条直线连接了至少三个点，另一条串起了剩下的点

A，“至少”表明≥3，如果第一条连接只有3个点，另一条连接仅2个点。
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请问linsonyeo和roddysong同学，如果第一条连接3个点，另一条连接剩下的点，不是意味着第二条连接剩下的3个点吗？

知行

哈哈 我真的理解成了 一笔连了。。。。。。

Rainbeauty

putting linsonyeo and sdcar2010, E should be chosen...

linsonyeo

是我眼花了,还是题目被修改了. 我记得上面贴的A选项是写 "另一条直线串起了剩下的两点",  怎么现在题目变成了"另一条直线串起了剩下的点". 那这样A当然也是确定的了. 选D.

echosongling

求救：

1. 一条直线连接了至少三个点，另一条串起了剩下的点


为何不能理解为两条线呢？

我觉得改选D呀

fyfly

选D!

rooneyfang

If I get it right A) says One line connected at least 3 dots. The rest of the dots are connected by another line.

A) should be sufficient. It clearly states that there are 3-5 dots are connected by one line and an extra line exists.

sdcar2010

If condition 1 says: One line has at least 3 points while ANOTHER LINE connects the rest, then condition 1 is sufficient.

If condition 1 says: One line has at least 3 points while ANOTHER LINE connects at least two out of the other three points, then condition 1 is insufficient.

If conditiion 2 says: One line connects ONLY 4 points, then condition 2 is sufficient.

If condition 2 says: One line connects at least 4 points, then condition 2 is insufficient.

kazemi

LZ的大牛说中关键了，还是看英文怎么表达吧，在这看中文的耗时间也没什么大意思啊