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prep practice 1中一些数学和语法题,没有在破解的材料中找到解法,希望各位帮忙解释一下。谢谢!

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楼主
发表于 2010-11-16 00:22:27 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
希望大家能帮我看看这些题该怎么解。都是我在破解材料中没有找到答案的。

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沙发
发表于 2010-11-16 00:34:01 | 只看该作者
数学:
首先一共有4×3×2×1=24种可能;
ABCD四个信封,abcd四封信;
a放入A时:acdb 和 adbc两种情况
所以共有2×4种
结论=8/24

语法题,用google搜吧,Manhattan SC给的答案我比牛。
板凳
 楼主| 发表于 2010-11-16 09:11:37 | 只看该作者
希望大家解读一下啊。。谢谢!!!!
地板
发表于 2010-11-16 20:40:37 | 只看该作者
Tanya prepared four different letters to be sent to four different addresses. For each letter, she prepared an envelope with its correct address. If the 4 letters are to be put into the envelopes at random, what is the probability that only one letter will be put into the envelope with its correct address?

Answer:

(C4,1*C2,1)/P44 = 1/3


C4,1: firstly, there are for chances for a letter is put into the correct envelope.
C2,1: secondly, there are two chances for a letter is put into the incorrect envelope.
Then, there is only one choice to put a letter into the incorrect envelope in the third and forth time.
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