我觉得答案有错

richardyam15

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale. The argument above is flawed because it fails to take into account A. changes in the population density of both Parkdale and Meadowbrook over the past four years B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale D. the violent crime rates in Meadowbrook and Parkdale four years ago E. how Meadowbrook's expenditures for crime prevention over the past four years compare to Parkdale's expenditures

答案选c。但是我坚信d才正确。希望大家帮忙看看～谢谢

sunli2829

答案就是D啊，LZ哪儿看到的C，这题逻辑就是问变化率和绝对量的，如今犯罪率的高低取决于四年前的绝对量和四年中的变化率，就是D,而且我都对了好几次答案啦

richardyam15

哦～谢了哈～我的答案是c哦，认为错误吧可能