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A certain junior class has 1000 students and a certain senior class has 800 students. among these students there are 60 sibling pairs, each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class , what is the probability that 2 students selected will be sibling pair 1) 3/40,000 2)1/3,600 3)9/2,000 4)1/60 5)1/15 Assume the junior siblings in the 60 sibling pairs are numbered as Js(junior sibling)1, Js2, Js3, .... , Js60. And there are 1000 students in a junior class. Also assume that the senior siblings in the 60 sibling pairs are numbered as Ss(senior sibling)1, Ss2, Ss3, .... , Ss60. And there are 800 students in a senior class.
We get to pick one from each class, a junior class and a senior class, and have to find the probability that the two will be a pair, i.e. (Js1, Ss1), (Js2, Ss2), ... , (Js60, Ss60).
Solution: 1. There are 60 possible siblings in a junior class to choose from = 60/1000 (here we do not care which sibling we pick as long as we pick the exact match in a senior class)
(Two different interpretations are possible from here) 2a. There are 60 siblings in a senior class and we must match our pick out of 60 the one we picked from the junior class = (60/800)*(1/60); or 2b. We do not care how many siblings in a senior class because we just have to pick the match out of 800 seniors = 1/800
1 * 2a = (60/1000)*(60/800)*(1/60) = 3/40000 1 * 2b = (60/1000)*(1/800) = 3/40000 |
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