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请教OG12 数学128题

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楼主
发表于 2010-7-17 15:14:34 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
128. A school administrator will assign each student in
a group of n students to one of m classrooms. If
3 < m < 13 < n, is it possible to assign each of the
n students to one of the m classrooms so that each
classroom has the same number of students assigned
to it?
(1) It is possible to assign each of 3n students to
one of m classrooms so that each classroom
has the same number of students assigned to it.
(2) It is possible to assign each of 13n students to
one of m classrooms so that each classroom
has the same number of students assigned to it.

答案选b,认为(1)不sufficient。并且解释是:
(1) Given that 3n is divisible by m, then n is
divisible by m if m = n = 9 (note that 3n = 27
and m = 9, so 3n is divisible by m) and n is
not divisible by m if m = 9 and n = 12 (note
that 3n = 36 and m = 9, so 3n is divisible by
m); NOT suffi cient.

可是这题不是很明确说了n是大于13的吗?怎么可能是9或者12呢。这个答案的解释看不懂。

我的理解是这个也是充分的。如果说3n可以被m整除,即m是3n的因数,m大于3,所以m不能是3的因数,所以m是因数。。请问我这样的理解有什么不对呢?
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沙发
发表于 2010-7-17 15:27:21 | 只看该作者
A錯在
3<M<13
其中6 因子有3 , 2
舉個例子
IF N=14 , M=6  , 14X3=42 , 42可被6整除
BUT 14無法被6整除
IF N=18 , M=6 ,18X3=54 54跟18都可被6整除
有兩種結果  故A選項錯嚕

OG解答我通常不理會  至少他給的ANS是對的
板凳
 楼主| 发表于 2010-7-17 15:51:09 | 只看该作者
多谢!
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