248. m^2<mn 可以化简到 m(m-n)<0 题目中给出 m<n 所以条件1 当m<=0时候 上面的式子既可以等于零,又可以大于0 所以不符合唯一性,排除 条件2 n<0 可以的出m<0 所以上面的式子 是大于零 符合唯一性 所以成立 大家验证下! 把答案确定下 -- by 会员 bulimu (2009/12/11 19:58:17) 248. I agre with the solution method, but could anyone kindly tell me why statement (1) is not sufficient? when m<=0, it is sufficient to get the answer --- which is, m^2不是<nm. so i feel statement 1 is sufficient as well as statement 2. sorry, 我的逻辑是很弱的。 -- by 会员 jillgaocn (2009/12/12 4:35:12)could anyone help me on my logic why it is wrong? i think about it over and over again and could not figure out. thank you so much in advance.
-- by 会员 jillgaocn (2009/12/12 10:24:37)
有道理,那应该条件一也对,反正怎么着都得不出<0来,唯一性应该是针对正确的答案来说的,
这两个答案都错,应该不牵扯错误的唯一性了,恩,有道理~~
那应该这道题就选D了,对吧~~ |