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条件一，mk为偶数，情况一m和k有一偶，k为m 的因子，进而推得，k为奇，m为偶，m/k中必存在因子2，则可以判断；情况二，都为偶，结果必定为偶。
条件二 可推得m和k必有一偶，同上述情况一
故选D
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发表于 2009-11-15 18:12:20
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