一道逻辑题,请高手解答

florachu

Q35:

In Patton City, days are categorized as having heavy rainfall (more than two inches), moderate rainfall (more than one inch, but no more than two inches), light rainfall (at least a trace, but no more than one inch), or no rainfall.  In 1990, there were fewer days with light rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the year was 20 percent higher in 1990 than in 1910.

 

If the statements above are true, then it is also possible that in Patton City

 

1. the number of days with heavy rainfall was lower in 1990 than in 1910

2. the number of days with some rainfall, but no more than two inches, was the same in 1990 as in 1910

3. the number of days with some rainfall, but no more than two inches, was higher in 1990 than in 1910

4. the total number of inches of rain that fell on days with moderate rainfall in 1990 was more than twice what it had been in 1910

5. the average amount of rainfall per month was lower in 1990 than in 1910

我怎么觉得A,B,C都对呢?

melodyflying

不知道答案是什么 我个人意见选D

A也可能 但D更靠谱

lz答案是什么

florachu

答案是A，但是其他几个选项哪里错了呢？？

genius_fang

A是有可能的，因为只要大于2inch就是heavy，所以1990年的总降水比1910年多，但是heavy的天数比1910年少，完全有可能的，比如1990年有50天时heavy，每次都是100inch，而1910年有200天，每次都是3inch，就符合A选项了~~~D不可能。因为1inch《moderate《2inch，题目说了1990年moderate的天数较少，又moderate的降水量=天数*每次的降水量。即不便天数两年一样，取极端，也只可能是两倍，更何况1990年的天数还比较少，所以无论如何也不可能降水量是1910年的两倍~B,C选项指的就是light和moderate，可以根据题目直接排除。E选项说每月平均较少，如果每个月都比1910年少，总降水量就不可能比1910年多20%，排除~所有选A！

[此贴子已经被作者于2009/10/9 9:01:07编辑过]

wanlin26

我也选的D, 看了4楼的解释,茅塞顿开, 厉害.

wanlin26

不过,对D还是觉得很迷惑,因为, 虽然题目中说MODERATE的天数少于1910年, 但天数和降雨量不能成正比啊, 比如1910年10天的雨,但只下了三个小时, 而1990年也许只有8天却下了多于三个小时,也许是八个小时,那么总的降雨量不就可能比1910年多了. 如何排除D项呢.?

genius_fang

楼上的，降水量应该是根据一天结束，统计累计下了多少inch雨水量的，而不是一下雨，就能算做多少inch的。也就相当于一个日平均降雨量的概念~~~我是这么认为的~呵呵！