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请问最近数学机井上的一道题

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楼主
发表于 2009-9-14 23:53:00 | 只看该作者

请问最近数学机井上的一道题

There are 1,200 respondents in a survey. And they are divided into three groups, such as A, B and C with percentage of 54%, 36% and 42% respectively (numbers may not be accurate). The percentage of A and B is 30%, what is the maximum number of C that is neither in A nor B.答案应该是312

请问这道题应该怎么做啊

沙发
发表于 2009-9-15 00:22:00 | 只看该作者

是480 A和B一共30% A是54%B是36% 我觉得A和B的全局是60%(54+36-30) 1-60%=40% 而C占42% 我觉得C非A/B占最大就是40%
1200*40%=480

板凳
发表于 2009-9-15 09:40:00 | 只看该作者

The table gives three factors to be considered when choosing an Internet service provider and the percent of the 1,200 respondents to a survey who cited that factor as important.  If 30 percent of the respondents cited both “user-friendly” and “fast response time,” what is the maximum possible number of respondents who cited “bargain prices,” but neither “user-friendly” nor “fast response time?”

Factor

Percent of Respondents

User-friendly

56%

Fast response time

48%

Bargain prices

42%

 

画韦恩图,U+F+B-UF-UB-FB-2UFB=100% AND UF=30
所求=[B-UB-FB-2UFB]=100%+UF-U-F=100%+30%-56%-48%=26%
B是已经确定的42%,如果UB or FB or 2UFB 有增加时候,整体[]将小于26%,因此,最大的可能就是26%1,200*26%=312

地板
发表于 2009-9-15 11:06:00 | 只看该作者
对于整体来说要 -2UFB, 但对于所要求的只要从B中减一次UFB呀。
5#
发表于 2009-9-15 11:59:00 | 只看该作者

恩,如果这么考虑的话二楼的是对的,应该只要减去一次UFB的,那就应该用二楼的做法!

谢谢提醒了!

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