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615一战750:阅读和逻辑机经

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21#
发表于 2009-6-16 15:25:00 | 只看该作者
以下是引用foxwill在2009-6-16 15:17:00的发言:

sigh~就是这句话,google真强大!

题目好像吧 which accounts for a preoccupation with astronomy, astrology, and calendrical science 换成了一个such as的说法,别的基本一样!!!

但为什么不是and explain(复数)呢?

22#
 楼主| 发表于 2009-6-16 15:35:00 | 只看该作者
从google的句子来看,应该是which 后面的accounts 和 explains 平行,而不是我前面说的那样,应该google的句子是对的。
23#
发表于 2009-6-16 18:29:00 | 只看该作者

楼主好厉害,逻辑回忆了七道,简直过目不忘。

赞一下!

24#
 楼主| 发表于 2009-6-17 00:02:00 | 只看该作者
以下是引用Eimi在2009-6-16 18:29:00的发言:

楼主好厉害,逻辑回忆了七道,简直过目不忘。

赞一下!

过奖了。。。其实是因为逻辑相对比较纠结,所以印象深一些。。。

25#
发表于 2009-6-17 02:39:00 | 只看该作者
写了那么多jj----造福同胞,祝雅思考试顺利啊!也考个牛分
26#
发表于 2009-6-17 09:31:00 | 只看该作者

逢730便进~!如果说720以下是凭借运气,那730以上,基本可以忽略运气成分!

27#
发表于 2009-6-17 10:34:00 | 只看该作者

感谢楼主!楼上滴,给我点运气720吧,嘻嘻~

28#
发表于 2009-6-17 12:57:00 | 只看该作者
恭喜楼主,谢谢分享!
29#
发表于 2009-6-17 13:16:00 | 只看该作者

T-4-Q20
                
天山-7-22

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

 

The argument above is flawed because it fails to take into account

 

  1. Changes in the population density of both Meadowbrook and Parkdale over the past four years.

  2. How the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

  3. The ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

  4. The violent crime rates in Meadowbrook and Parkdale four years ago 

  5. How Meadowbrooks’ expenditures for crime prevention over the past four years compare to Parkdale’s expenditures.

Answer is D.

Louzhu's answer is right.

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