数学 谁会？

jojo1130zy

Lists S and T consist of the same number of positive integers.  Is the median of the integers in S greater than the average (arithmetic mean) of the integers in T?

(1)   The integers in S are consecutive even integers, and the integers in T are consecutive odd integers.

(2)     The sum of the integers in S is greater than the sum of the integers in T.

	Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
	Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
	BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
	EACH statement ALONE is sufficient.
	Statements (1) and (2) TOGETHER are NOT sufficient.

WarlockNini

貌似C哦~

(1)可以推理出median=average

(2)可得出S的平均数大于T的平均数

综合得到S的中位数大于T的平均数~