From x<0.6y, => 0.6x<0.36y, which compares to w<0.6x, we have w<0.36y, and we know z<0.54y. So, 3*w<0.36*3y, and 2*z<0.54*2y, we got 3w<1.08y, (1) 2z<1.08y, (2), so (1) divided by (2), we got [(3w)/(2z)]<1, => 3w<2z, and w<(2/3)z , Z比W大百分制66.67
little 鱼, I might made a mistake. Look, from 3w<2z, we can get z>(3/2)w. So Suppose, w=1, then z>3/2, and z-w=3/2 -1 =1/2 Which is 50%, don’t you think so?
以下是引用zida在2004-2-10 9:56:00的发言: From x<0.6y, => 0.6x<0.36y, which compares to w<0.6x, we have w<0.36y, and we know z<0.54y. So, 3*w<0.36*3y, and 2*z<0.54*2y, we got 3w<1.08y, (1) 2z<1.08y, (2), so (1) divided by (2), we got [(3w)/(2z)]<1, => 3w<2z, and w<(2/3)z , Z比W大百分制66.67
Hi man, I think from (1), (2) we can not get 3w/2w <1, am i right? I think we can not get answer for this question. pls discuss...