今天做了prep-1的DS,发现我有一个很大的知识漏洞,现在有点晕了,想问问大家。 陈向东的书里面说截距intercept是直线与y轴相交的绝对值,所以截距肯定就是正数了。 但看prep DS-16: 16. 1275-!-item-!-187;#058&000656 Lines n and p lie in the xy-plane. Is the slope of line n less than the slope of line p ? (1) Lines n and p intersect at the point (5,1).
(2) The y-intercept of line n is greater than the y-intercept of line p.
我考虑(1)+(2)的时候是把截距分成两种情况考虑的,a)如果两条截在y的正半轴,且n的截距大于p的截距,那斜率肯定都是负的,有n的斜率小于p的斜率 ; b)如果两条线截在y的负半轴,且n的截距大于p的截距(我想的是此时截距就是绝对值,是个正数),斜率肯定都是正的,且n的斜率就大于p的斜率了。这样我觉得不能确定就选了E。 答案是C,好像只考虑两条线截在y的正轴的情况。 再看prep-ds-100: In the rectangular coordinate system shown above, does the line k (not shown) intersect quadrant II ? (1) The slope of k is -
(2) The y-intercept of k is -6. 这个时候截距又出现负数了,这个是怎么回事呀?? 当然还有prep-ds-132: 132. 13360-!-item-!-187;#058&009215 If l and k are lines in the xy-plane, is the product of the slopes of l and k equal to -1 ? (1) Line l passes through the origin and the point (1, 2).
(2) Line k has x-intercept 4 and y-intercept 2.
是否可以认为,如果题目中说截距是2,我就当成是正数算,题目中说截距是-2,我就当成是负数算? 不知道我表述清楚了没有? |