ChaseDream
搜索
返回列表 发新帖
查看: 436|回复: 5
打印 上一主题 下一主题

求教: 两道PREP上的题!!!!

[复制链接]
楼主
发表于 2007-1-15 01:14:00 | 只看该作者

求教: 两道PREP上的题!!!!

求教求教,都是DS的,没有思路

1. Is the Integer n odd?

1)n is divisible by 3

2)2n is divisible by twice as many possible integers as n

2 when positive integer n is divided by 3, the remainder is 2, and when positive integer T is divided by 5, tje remainder is 2, and what is the remainder when product nt is divided by 15?

1) n-2 is divisible by 5

2) t is divisible by 3


[此贴子已经被作者于2007-1-16 21:13:48编辑过]
沙发
 楼主| 发表于 2007-1-15 17:55:00 | 只看该作者
NN快出来啊
板凳
 楼主| 发表于 2007-1-16 21:13:00 | 只看该作者

再问两道:

1. how many integers n is ,2^n=n^2

Answer is 二个, but I only find 2, what is the onther one?

2. In the xy-plane, does the line with equation y=3x+2 contain the point (r,s)?

1)  (3r+2-s)(4r+9-s)=0

2) (4r-6-s)(3r+2-s)=0

DS: the answer is C, but I think both lead two 3r+2-s=0, why not D?

地板
发表于 2007-1-17 00:18:00 | 只看该作者

求教求教,都是DS的,没有思路

1. Is the Integer n odd?

1)n is divisible by 3

2)2n is divisible by twice as many possible integers as n


满足1的可为6 or 9, 2中 设n为奇数,n的因数为2,则2n的因子数为:[ 2的指数(此时为1)+1]x[那个奇数的指数(此时为1)+1] =4,满足。 若n为偶,则n因数中至少有一个2,假设只有一个2,提取出这个2后剩一个奇数,此时n的因数为4,2n的因子数为[ 2的指数(此时为2)+1]x[那个奇数的指数(此时为1)+1] = 6,不满足 Answer B

2
when positive integer n is divided by 3, the remainder is 2, and when
positive integer T is divided by 5, tje remainder is 2, and what is the
remainder when product nt is divided by 15?

1) n-2 is divisible by 5

2) t is divisible by 3

题是不是应该是“when positive integer n is divided by 3, the remainder is 2, and when
positive integer T is divided by 5, the remainder is 3,”  Answer C

5#
发表于 2007-1-17 01:07:00 | 只看该作者
以下是引用steffie在2007-1-16 21:13:00的发言:

再问两道:

1. how many integers n is ,2^n=n^2

Answer is 二个, but I only find 2, what is the onther one?

还有4

2. In the xy-plane, does the line with equation y=3x+2 contain the point (r,s)?

1)  (3r+2-s)(4r+9-s)=0

2) (4r-6-s)(3r+2-s)=0

DS: the answer is C, but I think both lead two 3r+2-s=0, why not D?

因为两个条件各自还会有另一个解满足条件(4r+9-s=0,4r-6-s=0),只有合起来才能保持唯一性

6#
 楼主| 发表于 2007-1-17 19:37:00 | 只看该作者
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2025-2-4 16:48
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2023 ChaseDream.com. All Rights Reserved.

返回顶部