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Fact: Asthma, a bronchial condition, is much less common ailment than hay fever, an allergic inflammation of the nasal passages.Fact: Over 95 percent of people who have asthma also suffer from hay fever.

If the information given as facts above is true, which of the following must also be true?

正确答案: E

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[求助]GWD2-40

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楼主
发表于 2006-11-27 11:45:00 | 只看该作者

[求助]GWD2-40

Fact:    Asthma, a bronchial condition, is much less common ailment than hay fever, an allergic inflammation of the nasal passages.

 

       Fact:      Over 95 percent of people who have asthma also suffer from hay fever.

 

If the information given as facts above is true, which of the following must also be true?

 

A.    Hay fever is a prerequisite for the development of asthma.

B.     Asthma is a prerequisite for the development of hay fever.

C.     Those who have neither hay fever nor asthma comprise less than 5 percent of the total population.

D.    The number of people who have both of these ailments is greater than the number of people who have only one of them.

E.     The percentage of people suffering from hay fever who also have asthma is lower than 95 percent.

答案选择是E,为什么不是A呢?请解释一下E选项为什么是正确的,谢谢^_^

沙发
发表于 2008-1-25 10:52:00 | 只看该作者

同问!! 请NN解答. THX~~~

板凳
发表于 2008-1-25 16:16:00 | 只看该作者

我非NN。。。

我觉得A是无关选项,must be true题目选项一定要来自原文,据此,没有信息支持推出时间两者的先后顺序

Fact1: Asthma < Hay Fever => Hay Fever > Asthma

Fact2: (95% A)+ H

=> (<95% H) + A

E:A发生的几率小,H发生的几率大,=>(当A发生了,H发生的几率)要大于(当H发生了,A发生的几率)

个人感觉有个小tip,文章说到percentage选项一定会有percentage,请NN验证~

地板
发表于 2008-1-25 16:17:00 | 只看该作者

我非NN。。。一只小小小菜鸟。。。

我觉得A是无关选项,must be true题目选项一定要来自原文,据此,没有信息支持推出时间两者的先后顺序

Fact1: Asthma < Hay Fever => Hay Fever > Asthma

Fact2: (95% A)+ H

=> (<95% H) + A

E:A发生的几率小,H发生的几率大,=>(当A发生了,H发生的几率)要大于(当H发生了,A发生的几率)

个人感觉有个小tip,文章说到percentage选项一定会有percentage,请NN验证~

5#
发表于 2008-1-26 05:01:00 | 只看该作者

假设

A 50; HF100

A5095%都有HF=50*95%=47.5;得出OnlyA只有2.5

A\B:谁是谁先决条件单从文章完全推不出来

C: neither hay fever nor asthma->这推不出因为全部人口文章未给

D: 都有HF=50*95%=47.5但大于只有一个的有两种可能

(1)47.5是大于只有A没错

(2)47.5是大于只有F未知

E: 都有HF=50*95%=47.5;假设全部人口200200*95%=190;所以可得出47.5<190

所以E

请指教

6#
发表于 2008-5-6 16:50:00 | 只看该作者
我感觉没有选项

已知A<F=〉(AF)/A>(AF)/F

又已知(AF/A>95% 那么(AF)/F95%那个大没法比。

7#
发表于 2008-5-6 17:15:00 | 只看该作者
这题画圈解比较好
8#
发表于 2008-5-18 16:15:00 | 只看该作者

我觉得可以这样想:设患a的总人数是S(a),h的总人数是S(h)

fact1 S(h)>>S(a)

fact2可知同时患两个毛病的人一共有95%S(a)这个数量既是people who have asthma also suffer from hay fever也是people suffering from hay fever who also have asthma

E选项说的不就是95%S(a)<95%S(h)吗?患两个毛病的人数是定量。在S(a) 中要占95%,但同样数量的人在S(h)中不会占到95%,因为基数大。

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