以下是引用TibetanMastiff在2006-8-7 21:16:00的发言:首先恭喜楼主。无比MM请看解释 let's assume that there are x large boxes have the middle boxes and (11-X) large boxes are empty therefore, there are 6x middle boxes let's continue assume that there are y middle boxes have the little boxes and (6X-Y) middle boxes are empty. therefore, there are 6y little boxes which are empty. At last, we can come out that there are (11-X)+(6x-y)+6y empty boxes; the total boxes tom has are 11+6x+6y for condition 1): (11-x)+(6x-y)+6y=56 -----> (x+y)=9, 所以11+6x+6y=65 for condition 2): 6y=42, we can't come out the result 11+6x+6y so, we can choose A 条理思路无比清晰~~ 明白了~~~~~谢谢TibetanMastiff GG~   |