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一道GMATPrep上的题

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楼主
发表于 2006-6-28 16:07:00 | 只看该作者

一道GMATPrep上的题

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?

answer: 2/3

what does it meant when it says "the tree was 1/5 taller than it was at the end of the 4th "?

请教思路。谢谢。

推荐
发表于 2006-10-17 15:26:00 | 只看该作者
以下是引用camilla2006在2006-6-28 16:07:00的发言:

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?

answer: 2/3

what does it meant when it says "the tree was 1/5 taller than it was at the end of the 4th "?

请教思路。谢谢。

设每年增加的constant amount 是 x, 那么,第6年的高度就是 4+6x,  第4年底的高度就是 4+4x。 根据题意,可得(4+6x)-(4+4x)=1/5*(4+4x).  解这个方程,可得:x=2/3

注意,tree 的增长是 by a contstant amount each year.  而不是 by a constant rate.

沙发
发表于 2006-6-28 16:18:00 | 只看该作者
意思是第六年末树的高度比第四年的高度高了1/5
板凳
发表于 2006-10-11 11:04:00 | 只看该作者

我列出了这样的式子, 4(1+r%)^6-4(1+r%)^4=1/5

但是请问怎么样简便运算呢?还是我的算式不对呢?

地板
发表于 2006-10-17 11:01:00 | 只看该作者
问再问~~
5#
发表于 2006-10-17 12:19:00 | 只看该作者

帮你顶, 我的式子和楼主是一样的...

??

6#
发表于 2006-10-17 14:41:00 | 只看该作者

2x=(4+4x)*1/5

x是每年增加的高度,左边等于第六年和第四年的高度差,右边是本来高4米,加上长了4年的高度,然后乘以1/5,不知道对不对?

8#
发表于 2006-10-17 15:47:00 | 只看该作者

赞同kevin_chee20

4+6x=6/5(4+4x)  ,x为每年的增加高度

9#
发表于 2006-10-17 21:51:00 | 只看该作者
3/F confuses the "constant amount" which should be height but not rate.
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